Answer :

We know that,


a3 + b3 + c3 – 3abc = (a + b + c) (a2 + b2 + c2 – ab – bc – ca)]


Using this formula, we get


= (a)3 + (2b)3 + (c)3 – 3 (a) (2b) (c)


= ( + 2b + c) [()2 + (2b)2 + (c)2 – () (2b) – (2b) (c) – (c) (a)]


= ( + 2b + c) (2a2 + 8b2 + c2 – 4ab – 2bc – ac)


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