Q. 9

# Factorize:</p

We know that,

a3 + b3 + c3 – 3abc = (a + b + c) (a2 + b2 + c2 – ab – bc – ca)]

Using this formula, we get

= ( a)3 + (2 b)3 + (c)3 – 3 ( a) (2 b) (c)

= ( + 2 b + c) [( )2 + (2 b)2 + (c)2 – ( ) (2 b) – (2 b) (c) – (c) ( a)]

= ( + 2 b + c) (2a2 + 8b2 + c2 – 4ab – 2 bc – ac)

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