Answer :
We have,
Let x + y = z
Then,
2 (x + y)2 – 9 (x + y) - 5
Now by using middle-term splitting, we get
= 2z2 - 9z - 5
= 2z2 – 10z + z – 5
= 2z (z – 5) + 1 (z – 5)
= (z – 5) (2z + 1)
Now,
Replacing z by (x + y), we get
2 (x + y)2 - 9 (x + y) – 5
= [(x + y) – 5] [2 (x + y) + 1]
= (x + y – 5) (2x + 2y + 1)
Hence,
The given expression can be factorized as:
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Genius Quiz | Division of Algebraic Expressions37 mins
Champ Quiz | Polynomials29 mins
Smart Revision | Polynomials Identities39 mins
Quiz | Division of Polynomials38 mins
NCERT | Master Polynomials51 mins
Factors & Remainder Theorem40 mins
Quiz | Imp. Qs. on Algebraic Identities65 mins
Introduction to Polynomials37 mins
Basic understanding of Polynomials37 mins
QUiz on Previous year NTSE Questions45 mins




















Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation


RELATED QUESTIONS :
75×75+2×
RD Sharma - MathematicsIf x+<span lang="
RD Sharma - MathematicsIf a2
RD Sharma - MathematicsFactorize:
</p
Factorize:
</p
Factorize:
</p
Factorize:
</p
If a1
RD Sharma - MathematicsFactorize:
</p
Factorize:
</p