Answer :

We know that,


a3 + b3 + c3 – 3abc = (a + b + c) (a2 + b2 + c2 – ab – bc – ca)]


Using this formula, we get


= (5a)3 + (b)3 + (4c)3 – 3 (5a) (b) (4c)


= (5a + b + 4c) [(5a)2 + b2 + (4c)2 – (5a) (b) – (b) (4c) – (5a) (4c)]


= (5a + b + 4c) (25a2 + b2 + 16c2 – 5ab – 4bc – 20ac)


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