Q. 7

# Factorize:

4(a + b) – 6 (a + b)^{2}

Answer :

We have,

At first, we’ll take (a+b) common from the expression.

= (a + b) [4 – 6 (a + b)]

Take 2 common out of [4 - 6(a+b)]= 2(a + b) (2 – 3a – 3b)

Hence,

The given expression can be factorized as:

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