Q. 424.2( 5 Votes )

If (x100</su A. 1

B. 2

C. -2

D. -3

Answer :

Let p (x) = x100 + 2x99 + k

It is given in the question that, (x + 1) is divisible by (x + 1)


So, p (-1) = 0


(-1)100 + 2 (-1)99 + k = 0


1 + 2 (-1) + k = 0


1 – 2 + k = 0


- 1 + k = 0


k = 1


Thus, the value of k = 1


Hence, option A is correct

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