Answer :

(i) We know that,


(a + b)3 = a3 + b3 + 3ab (a + b)


Using this formula, we get


= (3x)3 + (2)3 + 3 × 3x × 2 (3x + 2)


= 27x3 + 8 + 18x (3x + 2)


= 27x3 + 8 + 54x2 + 36x


(ii) We know that,


(a + b)3 = a3 + b3 + 3ab (a + b)


Using this formula, we get


= (3a)3 - (2b)3 - 3 × 3a × 2b (3a - 2)


= 27a3 – 8b3 – 18ab (3a – 2b)


= 27a3 – 8b3 – 54a2b + 36ab2


(iii) We know that,


(a + b)3 = a3 + b3 + 3ab (a + b)


Using this formula, we get


= (2/3x)3 + (1)3 + 3 × 2/3x × 1 (2/3x + 1)


= 8/27x3 + 1 + 2x (2/3x + 1)


=


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