Q. 234.3( 3 Votes )

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Answer :

Let y = e3x sin 4x 2x

Take log both sides:

log y = log (e3x sin 4x 2x)

log y = log (e3x ) + log (sin 4x) + log (2x)

log y = 3x log e+ log (sin 4x) + x log 2 {log xa = alog x}

log y = 3x + log (sin 4x) + x log 2 {log e = 1}

Differentiating with respect to x:

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