Q. 195.0( 1 Vote )

Find <span lang="

Answer :

let y = ex + 10x + xx


y = a + b + c


where a= ex; b = 10x ; c = xx




a= ex


Taking log both the sides:


log a= log ex


log a= x log e


{log xa = alog x}


log a= x {log e =1}


Differentiating with respect to x:







Put the value of a = ex



b = 10x


Taking log both the sides:


log b= log 10x


log b= x log 10


{log xa = alog x}


Differentiating with respect to x:









Put the value of b = 10x



c = xx


Taking log both the sides:


log c= log xx


log c= x log x


{log xa = alog x}


Differentiating with respect to x:









Put the value of c = xx





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