Answer :

We are given with an equation sin2y + cos(xy) = k , we have to find at x = 1, y = by using the given equation, so by differentiating the equation on both sides with respect to x, we get,


2siny cosy – sin(xy)[(1)y + x] = 0


[2siny cosy – xsin(xy)] = ysin(xy)



By putting the value of point in the derivative, which is x = 1, y = ,


(x = 1,y = π/4) =


(x = 1,y = π/4) =


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