Answer :

We are given with an equation y3 – 3xy2 = x3 + 3x2y, we have to find of it, so by differentiating the equation on both sides with respect to x, we get,


3y2 3[y2(1) + 2xy ] = 3x2 + 3[2xy + x2]


Taking terms to left hand side and taking common , we get,


[3y2 6xy 3x2] = 3x2 + 6xy + 3y2



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