Q. 303.7( 6 Votes )

If <span lang="EN

Answer :

We are given with an equation y = {logcosxsinx} {logsinxcosx} – 1 + sin – 1(), we have to find at


x = by using the given equation, so by differentiating the equation on both sides with respect to x, we get,


By using the properties of logarithms,


y = {logcosxsinx}2 + sin – 1()


y = {}2 + sin – 1()


= 2{}


= 2{}


= 2{}


Now putting the value of x = in the derivative solved above, we get,


(x = π/4) = 2{1} +


(x = π/4) = 2{1} +


(x = π/4) = 2{1} +


(x = π/4) = +


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