Q. 254.0( 4 Votes )

Find <span lang="

Answer :

let y = xsin x + (sin x)x


y = a + b


where a= xsin x; b = (sin x)x




a= xsin x


Taking log both the sides:


log a= log xsin x


log a= sin x log x


{log xa = alog x}


Differentiating with respect to x:









Put the value of a = xsin x :



b = (sin x)x


Taking log both the sides:


log b= log (sin x)x


log b= x log (sin x)


{log xa = alog x}


Differentiating with respect to x:











Put the value of b = (sin x)x :





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