Answer :
Let x = cos2θ
Now
Using 1 – 2sin2θ = cos2θ and 2cos2θ – 1 = cos2θ
Now
Using sin(A + B) = sinA cosB + cosA sinB
Considering the limits,
0 < x < 1
0 < cos 2θ < 1
Now,
Differentiating w.r.t x, we get
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