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RD Sharma - Volume 1

11. Differentiation

Exercise 11.1

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Exercise 11.2

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Exercise 11.3

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Exercise 11.4

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Exercise 11.5

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Exercise 11.6

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Exercise 11.7

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Exercise 11.8

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MCQ

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Very short answer

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Q. 8

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Class 12th RD Sharma - Volume 1 11. Differentiation

Answer :

We are given with an equation (x² + y²)² = xy, we have to find of it, so by differentiating the equation on both sides with respect to x, we get,

2(x² + y²)[2x + 2y] = y(1) + x

[4y(x² + y²) – x] = y – 4x(x² + y²)

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