We are given with an equation (x2 + y2)2 = xy, we have to find of it, so by differentiating the equation on both sides with respect to x, we get,
2(x2 + y2)[2x + 2y] = y(1) + x
[4y(x2 + y2) – x] = y – 4x(x2 + y2)
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