Q. 685.0( 4 Votes )

If prove that .

Answer :


We have 1 + cos(2θ) = 2cos2θ and 1 + cos(2θ) = 2sin2θ.

[ log(am) = m × log(a)]

On differentiating y with respect to x, we get

We know

[using chain rule]


We have sin(2θ) = 2sinθcosθ


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