Q. 265.0( 3 Votes )

Find , when

y = (sin x)cos x + (cos x)sin x

Answer :

let y = (sin x)cos x + (cos x)sin x


y = a + b


where a= (sin x)cos x; b = (cos x)sin x




a= (sin x)cos x


Taking log both the sides:


log a= log (sin x)cos x


log a= cos x log (sin x)


{log xa = alog x}


Differentiating with respect to x:











b = (cos x)sin x


Taking log both the sides:


log b= log (cos x)sin x


log b= sin x log (cos x)


{log xa = alog x}


Differentiating with respect to x:













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