Answer :

We have to find the derivative of x2ex with the first principle method, so,

f(x) = x2ex


by using the first principle formula, we get,


f ‘(x) =


f ‘(x) =


f ‘(x) =


[By using (a+b)2 = a2+b2+2ab]


f ‘(x) =


f ‘(x) =


[By using limx0 = 1]


f ‘(x) = x2ex + limh0 e(x+h) [h+2x]


f ‘(x) = x2ex + 2x ex


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