Answer :

Let y = sin (xx)


Take sin inverse both sides:


sin-1 y = sin-1 (sin xx)


sin-1 y = xx


Taking log both the sides:


log (sin-1 y) = log xx


log (sin-1 y) = x log x {log xa = alog x}


Differentiating with respect to x:











Put sin (xx) :




{sin2 x + cos2 x=1}



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