Answer :
Let y = sin (xx)
Take sin inverse both sides:
⇒ sin-1 y = sin-1 (sin xx)
⇒ sin-1 y = xx
Taking log both the sides:
⇒ log (sin-1 y) = log xx
⇒ log (sin-1 y) = x log x {log xa = alog x}
Differentiating with respect to x:
Put sin (xx) :
{sin2 x + cos2 x=1}
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