Q. 85.0( 1 Vote )

Differentiate the

Answer :

Let y = ex log x

Taking log both the sides:

log y = log (e)x log x

log y = x log x log e {log xa = alog x}

log y = x log x {log e = 1}

Differentiating with respect to x:

Put ex log x :

{ elog a = a; alog x = xa}

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