Q. 18 F4.3( 3 Votes )

Differentiate the

Answer :

let y = esin x + (tan x)x


y = a + b


where a= esin x ; b = (tan x)x




a= esin x


Taking log both the sides:


log a= log esin x


log a= sin x log e


{log xa = alog x}


log a= sin x {log e =1}


Differentiating with respect to x:







Put the value of a = esin x



b = (tan x)x


Taking log both the sides:


log b= log (tan x)x


log b= x log (tan x)


{log xa = alog x}


Differentiating with respect to x:











Put the value of b = (tan x)x :





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