Q. 273.6( 5 Votes )

Find <span lang="

Answer :

let y = (tan x)cot x + (cot x)tan x


y = a + b


where a= (tan x)cot x ; b = (cot x)tan x




a= (tan x)cot x


Taking log both the sides:


log a= log (tan x)cot x


log a= cot x log (tan x)


{log xa = alog x}


Differentiating with respect to x:












b = (cot x)tan x


Taking log both the sides:


log b= log (cot x)tan x


log b= tan x log (cot x)


{log xa = alog x}


Differentiating with respect to x:














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