Answer :

let y = x x + (sin x) x


y = a + b


where a= x x ; b = (sin x) x




a= xx


Taking log both the sides:


log a= log (x)x


log a= x log x


{log xa = alog x}


Differentiating with respect to x:











b = (sin x)x


Taking log both the sides:


log b= log (sin x)x


log b= x log (sin x)


{log xa = alog x}


Differentiating with respect to x:














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