Answer :
finding slope of the tangent by differentiating the curve
m(tangent) at (x1, y1) =
normal is perpendicular to tangent so, m1m2 = – 1
m(normal) at (x1, y1) =
equation of tangent is given by y – y1 = m(tangent)(x – x1)
equation of normal is given by y – y1 = m(normal)(x – x1)
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