Q. 3 F4.5( 2 Votes )

# Find the equation

finding slope of the tangent by differentiating the curve

m(tangent) at (3,0) = 10

normal is perpendicular to tangent so, m1m2 = – 1

equation of tangent is given by y – y1 = m(tangent)(x – x1)

y at x = 3

y = 32 + 4×3 + 1

y = 22

y – 22 = 10(x – 3)

y = 10x – 8

equation of normal is given by y – y1 = m(normal)(x – x1)

x + 10y = 223

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