Q. 3 F4.5( 2 Votes )

Find the equation

Answer :

finding slope of the tangent by differentiating the curve



m(tangent) at (3,0) = 10


normal is perpendicular to tangent so, m1m2 = – 1



equation of tangent is given by y – y1 = m(tangent)(x – x1)


y at x = 3


y = 32 + 4×3 + 1


y = 22


y – 22 = 10(x – 3)


y = 10x – 8


equation of normal is given by y – y1 = m(normal)(x – x1)



x + 10y = 223


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