Q. 19 A5.0( 1 Vote )

Find the point on the curve at which the tangents are parallel to x – axis

Answer :

Given:


The curve is = 1


Differentiating the above w.r.t x, we get the Slope of tangent,


= 0


= 0


Cross multiplying we get,


= 0


16x + 9y = 0


9y = – 16x


= ...(1)


(i)


Since, the tangent is parallel to x – axis


= tan(0) = 0 ...(2)


tan(0) = 0


= The Slope of the tangent = tan


From (1) & (2),we get,


= 0


– 16x = 0


x = 0


Substituting x = 0 in = 1,


= 1


y2 = 16


y = ±4


Thus, the required point is (0,4) & (0, – 4)


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