Q. 19 A5.0( 1 Vote )

# Find the point on the curve at which the tangents are parallel to x – axis

Given:

The curve is = 1

Differentiating the above w.r.t x, we get the Slope of tangent, = 0 = 0

Cross multiplying we get, = 0

16x + 9y = 0

9y = – 16x = ...(1)

(i)

Since, the tangent is parallel to x – axis = tan(0) = 0 ...(2) tan(0) = 0 = The Slope of the tangent = tan From (1) & (2),we get, = 0

– 16x = 0

x = 0

Substituting x = 0 in = 1, = 1

y2 = 16

y = ±4

Thus, the required point is (0,4) & (0, – 4)

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