Q. 19 A5.0( 1 Vote )

# Find the point on the curve at which the tangents are parallel to x – axis

Given:

The curve is = 1

Differentiating the above w.r.t x, we get the Slope of tangent,

= 0

= 0

Cross multiplying we get,

= 0

16x + 9y = 0

9y = – 16x

= ...(1)

(i)

Since, the tangent is parallel to x – axis

= tan(0) = 0 ...(2)

tan(0) = 0

= The Slope of the tangent = tan

From (1) & (2),we get,

= 0

– 16x = 0

x = 0

Substituting x = 0 in = 1,

= 1

y2 = 16

y = ±4

Thus, the required point is (0,4) & (0, – 4)

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