Q. 124.7( 3 Votes )

At what points on

Answer :

Given:


The curve is y = 2x2 – x + 1and the line y = 3x + 4


First, we will find The Slope of tangent


y = 2x2 – x + 1


(2x2) – (x) + (1)


= 4x – 1 ...(1)


y = 3x + 4 is the form of equation of a straight line y = mx + c,where m is the The Slope of the line.


so the The Slope of the line is y = 3(x) + 4


Thus, The Slope = 3. ...(2)


From (1) & (2),we get,


4x – 1 = 3


4x = 4


x = 1


Substituting x = 1in y = 2x2 – x + 1,we get,


y = 2(1)2 – (1) + 1


y = 2 – 1 + 1


y = 2


Thus, the required point is (1,2)


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