Q. 5 D4.7( 3 Votes )

Find the equation of the tangent and the normal to the following curves at the indicated points:

x = a sec t, y = b tan t at t.

Answer :

finding slope of the tangent by differentiating x and y with respect to t




Now dividing and to obtain the slope of tangent



m(tangent) at t =


normal is perpendicular to tangent so, m1m2 = – 1


m(normal) at t =


equation of tangent is given by y – y1 = m(tangent)(x – x1)



equation of normal is given by y – y1 = m(normal)(x – x1)



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