Q. 5 D4.7( 3 Votes )

# Find the equation of the tangent and the normal to the following curves at the indicated points:x = a sec t, y = b tan t at t.

finding slope of the tangent by differentiating x and y with respect to t

Now dividing and to obtain the slope of tangent

m(tangent) at t =

normal is perpendicular to tangent so, m1m2 = – 1

m(normal) at t =

equation of tangent is given by y – y1 = m(tangent)(x – x1)

equation of normal is given by y – y1 = m(normal)(x – x1)

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