Q. 35.0( 2 Votes )

# The equation of the normal to the curve y = x (2 – x) at the point (2, 0) is

A. x – 2y - 2

B. x – 2y + 2 = 0

C. 2x + y = 4

D. 2x + y – 4 = 0

Answer :

Given that y = x (2 – x)

⇒ y = 2x – x^{2}

Slope of the tangent

Slope at (2, 0) = 2 – 4 = -2

Equation of normal:

⇒2y=x-2

⇒ x – 2y – 2 = 0

Hence option A is correct.

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