# Find the equation of the tangent to the curve x2 + 3y – 3 = 0, which is parallel to the line y = 4x – 5.

finding the slope of the tangent by differentiating the curve  m(tangent) = equation of tangent is given by y – y1 = m(tangent)(x – x1)

now comparing the slope of a tangent with the given equation

m(tangent) = 4 x = – 6

since this point lies on the curve, we can find y by substituting x

62 + 3y – 3 = 0

y = – 11

therefore, the equation of the tangent is

y + 11 = 4(x + 6)

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