Q. 174.5( 2 Votes )

Find the equation of the tangent to the curve x2 + 3y – 3 = 0, which is parallel to the line y = 4x – 5.

Answer :

finding the slope of the tangent by differentiating the curve




m(tangent) =


equation of tangent is given by y – y1 = m(tangent)(x – x1)


now comparing the slope of a tangent with the given equation


m(tangent) = 4



x = – 6


since this point lies on the curve, we can find y by substituting x


62 + 3y – 3 = 0


y = – 11


therefore, the equation of the tangent is


y + 11 = 4(x + 6)


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