Q. 174.5( 2 Votes )
Find the equation of the tangent to the curve x2 + 3y – 3 = 0, which is parallel to the line y = 4x – 5.
Answer :
finding the slope of the tangent by differentiating the curve
m(tangent) = 
equation of tangent is given by y – y1 = m(tangent)(x – x1)
now comparing the slope of a tangent with the given equation
m(tangent) = 4
x = – 6
since this point lies on the curve, we can find y by substituting x
62 + 3y – 3 = 0
y = – 11
therefore, the equation of the tangent is
y + 11 = 4(x + 6)
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