Q. 44.3( 3 Votes )

Find a point on t

Answer :

Given:


The curve y = x3 – 3x


First, we will find the Slope of the tangent


y = x3 – 3x


(x3) – (3x)


= 3x3 – 1 )


= 3x2 – 3 ...(1)


The equation of line passing through (x0,y0) and The Slope m is y – y0 = m(x – x0).


so The Slope, m =


The Slope of the chord joining (1, – 2) & (2,2)




= 4 ...(2)


From (1) & (2)


3x2 – 3 = 4


3x2 = 7


x2 =


x =


y = x3 – 3x


y = x(x2 – 3)


y = (()2 – 3)


y = (( – 3)


y = ()



y = ()


Thus, the required point is x = & y = ()


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