Answer :

finding slope of the tangent by differentiating the curve




Finding y co – ordinate by substituting x in the given curve


2y2 – 6y + 4 = 0


y2 – 3y + 2 = 0


y = 2 or y = 1


m(tangent) at x = 2 is 0


normal is perpendicular to tangent so, m1m2 = – 1


m(normal) at x = 2 is , which is undefined


equation of normal is given by y – y1 = m(normal)(x – x1)


x = 2


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