Q. 6

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finding slope of the tangent by differentiating the curve  Finding y co – ordinate by substituting x in the given curve

2y2 – 6y + 4 = 0

y2 – 3y + 2 = 0

y = 2 or y = 1

m(tangent) at x = 2 is 0

normal is perpendicular to tangent so, m1m2 = – 1

m(normal) at x = 2 is , which is undefined

equation of normal is given by y – y1 = m(normal)(x – x1)

x = 2

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