Q. 75.0( 1 Vote )

# Prove that the cu

Answer :

Given:

Curves y2 = 4x ...(1)

& x2 + y2 – 6x + 1 = 0 ...(2)

The point of intersection of two curves is (1,2)

First curve is y2 = 4x

Differentiating above w.r.t x,

2y. = 4

y. = 2

m1 ...(3)

Second curve is x2 + y2 – 6x + 1 = 0

2x + 2y. 6 – 0 = 0

x + y. 3 = 0

y. = 3 – x ...(4)

At (1,2),we have,

m1  m1 = 1

At (1,2),we have,

m2  m2 = 1

Clearly, m1 = m2 = 1 at (1,2)

So, given curve touch each other at (1,2)

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