Q. 75.0( 1 Vote )

# Prove that the cu

Given:

Curves y2 = 4x ...(1)

& x2 + y2 – 6x + 1 = 0 ...(2)

The point of intersection of two curves is (1,2)

First curve is y2 = 4x

Differentiating above w.r.t x,

2y. = 4

y. = 2

m1 ...(3)

Second curve is x2 + y2 – 6x + 1 = 0

2x + 2y.6 – 0 = 0

x + y.3 = 0

y. = 3 – x

...(4)

At (1,2),we have,

m1

m1 = 1

At (1,2),we have,

m2

m2 = 1

Clearly, m1 = m2 = 1 at (1,2)

So, given curve touch each other at (1,2)

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

Find the equationRD Sharma - Volume 1

Find the equationMathematics - Board Papers

Find the equationRD Sharma - Volume 1

Find the equationRD Sharma - Volume 1

Find the equationRD Sharma - Volume 1

Find the equationRD Sharma - Volume 1

Find the equationRD Sharma - Volume 1

Find the conditioMathematics - Exemplar