Q. 11

# Find a point on t

Given:

The curve is y = 3x2 – 9x + 8

Differentiating the above w.r.t x

y = 3x2 – 9x + 8 = 2 3x2 – 1 – 9 + 0 = 6x – 9 ...(1)

Since, the tangent are equally inclined with axes

i.e, or  = The Slope of the tangent = tan  = tan( ) or tan( ) = 1or – 1 ...(2) tan( ) = 1

From (1) & (2),we get,

6x – 9 = 1 0r 6x – 9 = – 1

6x = 10 0r 6x = 8

x = or x = x = or x = Substituting x = or x = in y = 3x2 – 9x + 8,we get,

When x = y = 3( )2 – 9( ) + 8

y = 3( ) – ( ) + 8

y = ( ) – ( ) + 8

taking LCM = 9

y = ( )

y = ( )

y = ( )

y = ( )

when x = y = 3( )2 – 9( ) + 8

y = 3( ) – ( ) + 8

y = ( ) – ( ) + 8

taking LCM = 9

y = ( )

y = ( )

y = ( )

y = ( )

Thus, the required point is ( , ) & ( , )

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

Find the equationRD Sharma - Volume 1

Find the equationMathematics - Board Papers

Find the equationRD Sharma - Volume 1

Find the equationRD Sharma - Volume 1

Find the equationRD Sharma - Volume 1

Find the equationRD Sharma - Volume 1

Find the equationRD Sharma - Volume 1

Find the conditioMathematics - Exemplar