Q. 3 Q
Find the equation of the tangent and the normal to the following curves at the indicated points:
4x2 + 9y2 = 36 at (3 cos θ, 2 sin θ)
Answer :
finding the slope of the tangent by differentiating the curve
m(tangent) at (3 cos θ, 2 sin θ) = 
normal is perpendicular to tangent so, m1m2 = – 1
m(normal) at (3 cos θ, 2 sin θ) = 
equation of tangent is given by y – y1 = m(tangent)(x – x1)
equation of normal is given by y – y1 = m(normal)(x – x1)
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