Q. 17 A5.0( 1 Vote )

Find the point on

Answer :

Given:


The curve is = 1


Differentiating the above w.r.t x, we get the The Slope of a tangent,


= 0


Cross multiplying we get,


= 0


50x + 8y = 0


8y = – 50x


=


= ...(1)


(i)


Since, the tangent is parallel to x – axis


= tan(0) = 0 ...(2)


tan(0) = 0


= The Slope of the tangent = tan


From (1) & (2),we get,


= 0


– 25x = 0


x = 0


Substituting x = 0 in = 1,


= 1


y2 = 25


y = ±5


Thus, the required point is (0,5) & (0, – 5)


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