Answer :
Given in the given figure PQ || BC and AP: PB = 1: 2
We know that basic proportionality theorem states that if a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, then the other two sides are divided in the same ratio.
Since Δ APQ and ΔABC are similar,
Given
⇒ PB = 2AP
So,
we know that the ratio of areas of two similar triangles is equal to the square of the ratio of their corresponding sides.
∴ Area (ΔAPB): Area (ΔABC) = 1: 9
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