Q. 175.0( 1 Vote )

# In Fig. 4.236, <s

Answer :

Given in the given figure PQ || BC and AP: PB = 1: 2

We know that basic proportionality theorem states that if a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, then the other two sides are divided in the same ratio.

Since Δ APQ and ΔABC are similar, Given PB = 2AP

So, we know that the ratio of areas of two similar triangles is equal to the square of the ratio of their corresponding sides.  Area (ΔAPB): Area (ΔABC) = 1: 9

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