Given two poles of heights 6 m and 11 m stand vertically upright on a plane ground. Distance between their foot is 12 m.
Let CD be the pole with height 6 m. AB is the pole with height 11m and DB = 12 m
Let us assume a point E on the pole AB which is 6m from the base of AB.
Hence AE = AB – 6 = 11 – 6 = 5m
We know that the Pythagoras theorem state that in a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
Now, in right triangle AEC,
⇒ AC2 = AE2 + EC2
Since CDEB forms a rectangle and opposite sides of rectangle are equal,
⇒ AC2 = 52 + 122
= 25 + 144
⇒ AC = 13
∴ The distance between their tops is 13 m.
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