# In Fig. 4.179, are on the same base BC. If AD and BC intersect at O. Prove that

We know that area of a triangle = 1/2 x base x height

Since, ΔABC and ΔDBC are one same base.

Therefore ratio between their areas will be as ratio of their heights.

Let us draw two perpendiculars AP and DM on line BC

In ΔALO and ΔDMO,

∠ALO =∠DMO (Each is 90°)

∠AOL = ∠DOM (Vertically opposite angle)

∠OAL = ∠ODM (remaining angle)

Therefore ΔALO ~ ΔDMO (By AAA rule)

Therefore AL/DM = AO/DO

Therefore,

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