Q. 114.5( 8 Votes )
ABCD is a square. F is the mid-point of AB. BE is one third of BC. If the area of ΔFBE = 108 cm2, find the length of AC.
According to the question, the figure is :
∵ ABCD is a square. Hence, AB = BC = CD = DA
∵ F is the midpoint of AB.
∴ Length of BF = AB/2 = BC/2 (∵ AB = BC)
Given that, BE = BC/3
In ΔFBE, ∠B = 90° and Area of ΔFBE = 108 cm2
⇒ BC2 = 108 × 12
⇒ BC2 = 36 × 36
⇒ BC = 36 cm2
AC is the diagonal of the ABCD.
⇒ AC = 36√2 = 50.904 cm
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