Q. 255.0( 1 Vote )

If ABC is an isosceles triangle and D is a point on BC such that, then
A. AB2 - AD2 = BD. DC

B. AB2 - AD2 = BD2 - DC2

C. AB2 + AD2 = BD. DC

D. AB2 + AD2 = BD2 - DC2

Answer :

Given ABC is an isosceles triangles and AD BC.



We know that in an isosceles triangle, the perpendicular from the vertex bisects the base.


BD = DC


We know that the Pythagoras theorem state that in a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.


Now, in right triangle ABD,


AB2 = AD2 + BD2


AB2 – AD2 = BD2


AB2 – AD2 = BD (BD)


Since BD = DC,


AB2 – AD2 = BD (DC)

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