Q. 255.0( 1 Vote )

If ABC is an isosceles triangle and D is a point on BC such that, then
A. AB2 - AD2 = BD. DC

B. AB2 - AD2 = BD2 - DC2

C. AB2 + AD2 = BD. DC

D. AB2 + AD2 = BD2 - DC2

Answer :

Given ABC is an isosceles triangles and AD BC.

We know that in an isosceles triangle, the perpendicular from the vertex bisects the base.


We know that the Pythagoras theorem state that in a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

Now, in right triangle ABD,

AB2 = AD2 + BD2

AB2 – AD2 = BD2

AB2 – AD2 = BD (BD)

Since BD = DC,

AB2 – AD2 = BD (DC)

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