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# If ABC is an isosceles triangle and D is a point on BC such that, thenA. AB2 - AD2 = BD. DCB. AB2 - AD2 = BD2 - DC2C. AB2 + AD2 = BD. DCD. AB2 + AD2 = BD2 - DC2

Given ABC is an isosceles triangles and AD BC.

We know that in an isosceles triangle, the perpendicular from the vertex bisects the base.

BD = DC

We know that the Pythagoras theorem state that in a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

Now, in right triangle ABD,

AB2 – AD2 = BD (BD)

Since BD = DC,

AB2 – AD2 = BD (DC)

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