Answer :

Given in an isosceles ΔABC, AB = AC = 25 cm and BC = 14 cm


Here altitude from A to BC is AD.


We know in isosceles triangle altitude on non-equal sides is also median.


BD = CD = BC/2 = 7 cm


Applying Pythagoras Theorem,


AB2 = BD2 + AD2


252 = 72 + AD2


AD2 = 625 – 49 = 576


AD = 24


Measure of altitude from A to BC is 24 cm

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