Q. 425.0( 2 Votes )

In an isosceles t

Answer :

Given in isosceles ΔABC, AC = BC and AB2 = 2AC2



In isosceles ΔABC,


AC = BC, so B = A [Equal sides have equal angles opposite to them]


AB2 = 2AC2


AB2 = AC2 + AC2


AB2 = AC2 + BC2


ΔABC is right angle triangle with C = 90°

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