ABCD is a paralle

Given :- ABCD is a parallelogram

To prove :- BP x DQ = AB x BC

Proof:-








In ΔABP and ΔQDA

<B = <D (Opposite angles of parallelogram)

<BAP = <AQD (Alternative interior angle)

Then, ΔABP ~ ΔQDA

SO, (Corresponding parts of similar triangle area proportion) But, DA = BC (Opposite side of parallelogram)


But DA = BC ( opposite sides of parallelogram)

Then,

Or, AB x BC = QD X BP

Hence proved