Q. 173.6( 16 Votes )

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Answer :

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We know


PQBC


Area () =Area ()


Area () =Area ()- Area ()


2Area ()= Area () ………(i)


In


A=A [Common]


APQ=B [Corresponding angle]


ABCAPQ


Area() =AP2


Area () AB2


Area() =AP2


Area () AB2 [By using (I)]


1= AP2


2 AB2


=AP/AB


=


= -


=1-BP/AB


BP/AB=1-


BP/AB=

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