Answer :
We know
PQ∥BC
Area (
) =Area (
)
Area (
) =Area (
)- Area (
)
2Area (
)= Area (
) ………(i)
In 
∠A=∠A [Common]
∠APQ=∠B [Corresponding angle]
ABC
APQ
Area(
) =AP2
Area (
) AB2
Area(
) =AP2
Area (
) AB2 [By using (I)]
1= AP2
2 AB2
=AP/AB
=
=
-
=1-BP/AB
BP/AB=1-
BP/AB= 
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