Q. 103.7( 3 Votes )

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Answer :

We have, D and E as the midpoint of AB and AC

So, according to the midpoint therom

DE||BC and DE = 1/2 BC……………..(i)


<A = <A (Common)

<ADE = <B (Corresponding angles)

Then, ΔADE ~ ΔABC (By AA similarity)

By area of similar triangle theorem

Area ΔADE/ Area ΔABC = DE2/BC2

Or, (1/2BC)2/(BC)2

Or, 1/4

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