Q. 103.7( 3 Votes )

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Answer :

We have, D and E as the midpoint of AB and AC


So, according to the midpoint therom


DE||BC and DE = 1/2 BC……………..(i)


In ΔADE and ΔABC


<A = <A (Common)


<ADE = <B (Corresponding angles)


Then, ΔADE ~ ΔABC (By AA similarity)


By area of similar triangle theorem


Area ΔADE/ Area ΔABC = DE2/BC2


Or, (1/2BC)2/(BC)2


Or, 1/4


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