Q. 1 A5.0( 1 Vote )
Find the principa
Answer :
Let sec–1(–√2) = y
⇒ sec y = –√2
= – sec = √2
= sec
= sec
The range of principal value of sec–1is [0, π]–{}
and sec = –√2
∴ The principal value of sec–1(–√2) is .
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