Q. 4

# If sin–1x + sin–1y + sin–1z + sin–1t = 2π, then find the value ofx2 + y2 + z2 + t2.

Range of sin–1x is .

Give that sin–1x + sin–1y + sin–1z + sin–1t = 2π

Each of sin–1x, sin–1y, sin–1z, sin–1t takes value of .

So,

x = 1, y = 1, z = 1 and t = 1.

Hence,

= x2 + y2 + z2 + t2

= 1 + 1 + 1 + 1

= 4

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