Answer :

Given sin-1 (cos π/9)


We know that cos θ = sin (π/2 – θ)


= sin-1 (sin (π/2 - π/9))


= sin-1 (sin 7π/18)


We know that sin-1 (sin θ) = θ


= 7π/18


sin-1 (cos π/9) = 7π/18


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