Answer :

sin–1(sin x) = x


Provided x ϵ ≈ [–1.57,1.57]


And in our equation x is 3 which does not lie in the above range.


We know sin[π – x] = sin[x]


sin(π – 2) = sin(2)


Also π–2 belongs in


sin–1(sin2) = π–2


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