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Answer :

As, tan–1(tan x) = x


Provided x ϵ


Here our x is 12 which does not belong to our range


We know tan(nπ –θ) = –tan(θ)


tan(θ –2nπ ) = tan(θ)


Here n = 4


tan(12–4π ) = tan(12)


Now 12–4π is in the given range


tan–1 (tan 12) = 12–4π.


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